A satellite of mass 200 kg revolving in a circular orbit of radius 2 R around the earth has kinetic energy E. Then its angular momentum will be
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Answer:
K.E.=
2r
GM
e m
=
2×(6670×10
3
)
(6.67×10
−11
)(6.0×10
24
)(200)
=6.0×10
9
joule.
Gravitation potential energy,
U=
r
GM
e
m
=−12.0×10
9
joule
∴ Total energy, T=U+K=−6.6×10
9
joule.
Explanation:
hope it helps might be harder but yea
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