Solve the following
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Answer:
65 and 65 E angle and F
Step-by-step explanation:
50+65+65 -180
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0
Answer:
in ∆DEF <D =50° & DE= DF
Therefore, <DEF = <DFE
Hence, <DEF+<DFE+<D=180°
or, <DEF+<DFE = 180°-<D
or, <DEF + <DEF = 180°- 50° [as
<DEF =<DFE ]
or, 2<DEF = 130°
or, <DEF = 130°/2
= 65°
THEREFORE Angele E =65° and <F = 65°
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