Question

A satellite of mass m is in the orbit round the earth at a distance of 2.5R above its surface. If gravitational field strength at surface of earth is g
calculate the centripetal force acting on the satellite.​

Answer 1

Answer:

mv^2/3.5R.

Explanation:

Since, the satellite of mass m is rotating around the earth in a orbit so, the acceleration will be.

Acceleration is a=v^2/R where R is the radius of the earth. Since, the orbit is at a height h then the acceleration is a=v^2/(R+h).

So, the centripetal force will be F=ma. Since the height h=2.5R given. So, the force will be F=m*v^2/(R+2.5R). Which on solving we will get that mv^2/3.5R. Which will be the centripetal force of the body acting on the satellite.

Answer 2

Explanation:

this way it can be solved

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