Physics, asked by punideshwari, 9 months ago

A satellite orbiting around earth in an orbit
radius R is shifted to an orbit of radius 2R

Time taken for one revolution will become-
[AIPMT-1993, BHU-201
(1) 8 times
(2) 2 times
(3) 2.5 times
(4) 2.8 times​

Answers

Answered by 111801015
5

Answer:

(4) 2.8 times

Explanation:

As we all know T^2 = kR^3, this implies

T1/T2 = (R1/R2)^3/2

Given T1=T (let), R1=R and R2=2R

T2 = T1 x (R2/R1)^3/2

    = T x (2R/R)^3/2

    = T x (2)^3/2

    = 2.828 x T .       (Soln.)

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