A satellite orbiting around earth in an orbit
radius R is shifted to an orbit of radius 2R
Time taken for one revolution will become-
[AIPMT-1993, BHU-201
(1) 8 times
(2) 2 times
(3) 2.5 times
(4) 2.8 times
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Answer:
(4) 2.8 times
Explanation:
As we all know T^2 = kR^3, this implies
T1/T2 = (R1/R2)^3/2
Given T1=T (let), R1=R and R2=2R
T2 = T1 x (R2/R1)^3/2
= T x (2R/R)^3/2
= T x (2)^3/2
= 2.828 x T . (Soln.)
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