Question

A satellite orbiting in a circular orbit of radius R completes one revolution in 3 hours. If orbital radius of a geostationary satellite is 42000 km then the value of R is???​

Answer 1

Answer:

10500 km

Explanation:

Orbit of radius = r (Given)

Distance of the geostationary satellite = 42000km (Given)

Time of one revolution = 3 hrs (Given)

Let T1 and R1 represent the time period and radius of the geostationary satellite.  

Similarly, T2 and R2 represent the time period and radius of the earth.

(T1/T2)² = (R1/R2)³  -where T1 = 3 hr, T2 = 24 hr and R2 = 42000 km

Hence,

(3/24)² = (R1/ 42000)³

(1/64 )1/3= R1/42000

R1 = 42000/4

R1 = 10500 km