A satellite revolves with the time period of 84.3 min at a height of 40 km from the surface of the earth the speed of the satellite is (radius of the earth is 6400km)
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Answer:
8 km/s
Explanation:
Time period = Circumference of circular orbit / (Orbital speed)
Orbital speed = Circumference / Time period
= (2πr) / (84.3 min)
= [2 × 22/7 × (6400 km + 40 km)] / (84.3 min)
= [44/7 × 6440 km] / (84.3 × 60 s)
= 40480 km / (5058 s)
≈ 8 km/s
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8 km
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