A satellite which is geostationary in a particular
orbit is taken to another orbit. Its distance from
the centre of earth in new orbit is 2 times that of
the earlier orbit. The time period in the second
orbit is
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Answer:
First time T^2×R^3
Second time T^2×(2R) ^3
T1/T=(2R) ^3/(R) ^3/2=(2) ^3/2
T1 =2^3/2T (T =24 hour for geostationary satellite)
T=,2√2×24= 48√2
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