Question

A saturated solution of AgCl was found to have a Concentration of 1.3×10‐⁵moldm-3. What is the solubility product of AgCl?​

Answer 1

Answer:

Ksp = 1.7×10-10

Agcl =Ag++cl-

Let the solubility for each ion is S.

Then, ksp = [Ag+][cl-]

so, S2 = 1.7×10-10

Therefore S = 1.3×10-5