Question

A says to B “my present age is five times your that age when I was an old as you are now. If the

sum of their present ages is 48 years, find their present ages.​

Answer 1

Answer:

Step-by-step explanation:

Given :

A says to B “my present age is five times your that age when I was an old as you are now.

If the sum of their present ages is 48 years, find their present ages.​

Solution :

Statement 1 :

A says to B “my present age is five times your that age when I was an old as you are now.

Modified statement :

A is 5 times as old as B,.

⇒ Present age of B = 5 times the present age of A

Let the age of A be x,

Let the age of B be y,.

⇒ y = 5x    ...(i)

Statement 2 :

If the sum of their present ages is 48 years, find their present ages.​

Modified statement :

The total of their present age is 48.

⇒ x + y = 48,.

By substituting value of y in equation (i) , We get,.

⇒ x + (5x) = 48

⇒ 6x = 48

⇒ x = $\frac{48}{8}$

⇒ x = 8,.

∴ The present age of A is 8 years.

By substituting value of x in (i),

We get,

⇒ y = 5x

⇒ y = 5 × 8

⇒ y = 40

∴ The present age of B is 40 years.

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

A is 40 years old and B is 8 years old.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

A's present age = 5 times of B's age

Sum of their present ages = 48

To find :

Their Present Ages

Solution :

Consider the age of A as y

Consider the age of B as x

A is 5 times the age of B

$\boxed{\sf{y = 5x}}$

Sum of their Ages = 48

Age of A + Age of B = 48

★ $\boxed{\sf{(5x)+x=48}}$

$\sf{\implies} \: (5x) +x = 48$

$\sf{\implies} \: 6x = 48$

$\sf{\implies} \: x = \dfrac{48}{6}$

$\sf{\implies} \: x = 8$

B's age = 8 years

$\rule{300}{1.5}$

★ Value of 5x

$\sf{\implies} \: 5 \times 8$

$\sf{\implies} \: 40$

A's age = 40 years

$\rule{300}{1.5}$

$\therefore$ A is 40 years old and B is 8 years old.