Physics, asked by ishita122, 1 year ago

a scale is divided into 0.5 mm division if 20 divisions of this scale are divided into 25 equal parts of a vernier calculate the least count

Answers

Answered by eulit
1
vernier caliper is an instrument to measure the internal and external diameters of small tubes. the least count is finest
Answered by Deepsbhargav
7
hey friend!!!

Solution:

1 M.S.D. = 0.5 mm

25 V.S.D. = 20 M.S.D.

Thus, 1 V.S.D. = 20/25 M.S.D. = 0.8 M.S.D. = 0.8 x 0.5 mm = 0.4 mm

Now, Least Count of Vernier Caliper = 1 M.S.D. – 1.V.S.D. = 0.5 mm – 0.4 mm = 0.1 mm

Hence least count of vernier calliper is 0.1 mm

hope it will help you.
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