Question

A schedule speed of 45 km, per hour is required between two stops 1.5 km apart. The duration of stop is 20 seconds. The acceleration is 2.4 km phps and retardation is 3.2 km phps. For a simplified trapezoidal curve the maximum speed over the mil will be

Answer 1

74 km per hour ------ maximum speed over the mil will be
make me brainlist if it's correct

Answer 2

Programmed Speed:

The ratio of the distance travelled between two stops to the total race time, including the stopping time, is called the programmed speed.

It is denoted by Vs

Vs = D/Ts

Where

D is the distance between stops

Ts is the programmed time in hours

Ts = Total Travel Time + Stop Time (Tr + Th)

Calculation:

Given:

Vs = 45 km/h

= 45 × (5 / 18)

= 25 / 2 (m/sec)

D = 1.5 km

= 1.5 × 1000

= 1500 m

stop time Th = 20 sec.

total running time Tr =?

25 / 2 = 1500 / (Tr + 20)

⇒ Tr + 20 = 120

⇒ Tr = 100 seconds

So the actual travel time of the train is 100 seconds

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