Question

a school auditorium is 50 m long and 30 m wide . this auditorium is surrounded by a verandah 5m wide on the outside of it . find the area of the verandah if tiles of 50 cm ×50 cm are fixed on the verandah how many tiles will be required

Answer 1

Area with veranda 60x40 = 2400sq m.
Area of auditoriu6. 50x30= 1500 sq.m
Area of veranda. = 900 sq.m
no. of tiles needed = 900x100x100/ (50* 50)=3600.

Answer 2

The inner length = 50

The inner breadth = 30

The outer length = inner.L + 2*W

= 50*2*5 = 60 m

The outer breadth = inner.b+2W

= 30+2*5 = 40

Area of the outer rectangular = l*b

= 60*40 = 2400 sq.m

Area of the inner rectangular = l*b

= 50*30 = 1500 sq.m

Area of the verandah = 2400 - 1500

= 900 sq.m

1 sq.m = 10000 sq.cm

ஃ 900 sq.m = 900* 10000

= 9000000 sq.cm

Area of the one tile = 50*50

= 2500 sq.cm

No.of tiles required = 9000000/2500

= 3600 tiles.