A school awarded 38 medals in football, 15 in
basket ball and 20 in cricket. Suppose these medals
went to a total of 58 students and only three students
got medals in all three sports. If only 5 students got
medals in football and basketball, then the number
of medals received in exactly two of three sports is___.
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2
Answer:
Let x get exactly 1 medal
and y get 2 medal
as stated 3 students get 3 medals.
therefore
x+ 2y +3 ×3. = 38 + 15 +20 =73
x +2y +9 = 73
x +2y = 73 -9
x +2y = 64
Also,
x + y + 3 =58 {total number of participants}
x+ y =58-3
x+y = 55
Now, using elimination method to solving this
x + 2y = 64
x + y = 55
- - -
● y = 9
then
x + y =55
x + 9 =55
x =55-9
x =46
then
46 students get exactly 1 medal
9 students get 2 medals
with regards
hope its help you!
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