Math, asked by janvikandhol1, 1 year ago

a school decided to award prizes to students for three values discipline cleanliness of environment and regularity in attendance the number of students getting prizes in the three categories are in the ratio 1: 2 :3 if product of ratio is 162 then
find the number of students getting prices for each value ​

Answers

Answered by abf7
4

let it be 1x ,2x and 3x

=1x×2x×3x=162

=6×3x=162

=9x=162

=x=162÷9

=x=18

=2x=2×18=36

=3x=3×18=54

therefore,no.of students getting prize in cleanliness=18

discipline=36

regularity=54

hope it helps

Answered by loknathbhagat1970
1

Answer:

let the the number of prizes given to students for three values- discipline, cleanliness of environment, and regularity in attendance be 1x 2x and 3x respectively.

then according to question,

1x × 2x × 3x = 162

6x ^{3}  = 162

x {3} = 162 \div 6

x {3} = 27

x =  \sqrt[3]{27}

x =   \sqrt[3]{3 \times 3 \times 3}

x = 3

Therefore,

1x=1×3=3

2x=2×3=6

3x=3×3=9

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