A school play ground is rectangular in shape with length 80 m and breadth 60 m. A cemented pathway running all around it on its outside of width 2 m is built. Find the cost of cementing if the rate of cementing 1 sq. m is `20.
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Answered by
26
AREA OF PLAYGROUND = 80*60=4800
Now, According to question cemented pathway outside it
therefore, LENGTH WILL BE= 80+2+2=84
BREADTH WILL BE =60+2+2=64
Now AREA OF PATH INCLUDING PLAYGROUND=84*64=5376
hence area of cemented path only = 5376-4800=576
cost of cementing =576*20=11520
Now, According to question cemented pathway outside it
therefore, LENGTH WILL BE= 80+2+2=84
BREADTH WILL BE =60+2+2=64
Now AREA OF PATH INCLUDING PLAYGROUND=84*64=5376
hence area of cemented path only = 5376-4800=576
cost of cementing =576*20=11520
Answered by
17
Area of the cemented pathway = (84×64) - (80×60)
= 5376 - 4800
= 576 m²
Cost of cementing per m² = $ 20
Cost of cementing 576 m² = 20 × 576
= $ 11520
= 5376 - 4800
= 576 m²
Cost of cementing per m² = $ 20
Cost of cementing 576 m² = 20 × 576
= $ 11520
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