Question

A school team won 6 games this year against 4 games won last year. What is the percent

increase ?​

Answer 1

Answer:

won in this year =6

won in last year = 4

increase in no. of games won=6-4=2

percentage increase =increase in no. of games won/no. of games won last year×100

=2/4×100

=200/4=50%

Answer 2

Answer:

Given that the school won 6 games this year against 4 won last year

Increase in number of wins = 6 – 4 = 2

Hence per cent increase = (2/4) × 100

= (1/2) × 100

= 50% Thus the percentage increase in winning the games this year is 50%.