Question

a scientist claims to have developed a heat engine working between 27 degree C and 727 degree C with efficiency x.​

Answer 1

$\boxed{\bold {\green{Answer}}}$

70%

$\boxed{\bold {\green{Explanation}}}$

Given:

• Sink temp(T2) = 27°C = 300k
• Source temp (T1) = 727°c = 1000k

To Find:

Efficiency of engine

Solution:

w.k.t

$\boxed{\bold {\pink{\eta = 1 - \dfrac{T_2}{T1}}}}$

$\mathsf{\eta = 1 - \dfrac{300}{1000}}$

$\mathsf{\eta =\dfrac{1000-300}{1000}}$

$\mathsf{\eta =\dfrac{700}{1000}}$

$\mathsf{\eta =0.7}$

Now,

$\mathsf{\eta =0.7 \times 100}$

$\mathsf{\eta = 70}$

Eta % = 70%