A scooter acquires a speed of 36 km/h in 5s just after the start . calculate the acceleration of the scooter.
Anonymous:
It's 2m/s²
Answers
Answered by
28
Acceleration= v-u/t
therefore here
v=36 km/h(10m/s)
u=0 km/h(0m/s)
t=5sec
So, v-u/t
10-0/5 =10/5
Answer is 2 m/s2
therefore here
v=36 km/h(10m/s)
u=0 km/h(0m/s)
t=5sec
So, v-u/t
10-0/5 =10/5
Answer is 2 m/s2
Answered by
26
Heya user
Here's your answer !!
__________
Speed in km / hr = 36 km / hr .
So , speed in m / s = 36 × 5 / 18 m / s
= 10 m / s .
Time taken = 5 secs .
Final velocity = 10 m / s
Initial velocity = 0
So , acceleration = v - u / t
= ( 10 - 0 ) m / s / 5 s
= 10 / 5 m / s²
= 2 m / s² . [ Answer ] .
___________
Hope it helps !!
Here's your answer !!
__________
Speed in km / hr = 36 km / hr .
So , speed in m / s = 36 × 5 / 18 m / s
= 10 m / s .
Time taken = 5 secs .
Final velocity = 10 m / s
Initial velocity = 0
So , acceleration = v - u / t
= ( 10 - 0 ) m / s / 5 s
= 10 / 5 m / s²
= 2 m / s² . [ Answer ] .
___________
Hope it helps !!
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