Question

a scooter acquires a velocity of 36 km/h in 10s just after the start. calculate the acceleration of the scooter

Answer 1

firstly change km/h into m/s
so,36km/h=36into5/18=10m/s.
so,a=v-u/t
a=10-0/10
a=10/10
a=1m/s square

Answer 2

$u = 0 mps\\ v = 36kmph = 36 \times \frac{5}{18} = 10mps \\t = 10 \: s \\ a = \frac{v - u}{t} = \frac{10 - 0}{10} = \frac{10}{10} \\ = 1$
So, acceleration is 1m/s^2.