Question

. A scooter acquires a velocity of 36 km/hr in 5s just after the start. Calculate the acceleration.

Answer 1

Given :

• Initial velocity of Scooter, u = 0
• Final velocity of Scooter, v = 36 km/h
• Time for acquiring final velocity, t = 5 s

To find :

• Acceleration of Scooter, a =?

Formula required :

• First equation of motion

       v = u + a t

[ Where v is velocity, u is initial velocity, a is acceleration and t is time taken ]

Solution :

Converting Final velocity given in km/h into m/s

→ v = 36 km/h

→ v = 36 × 5/18  m/s

→ v = 2 × 5  m/s

→ v = 10 m/s  

 

Calculating acceleration of Scooter

Using first equation of motion

→ v = u + a t

→ 10 = 0 + a ( 5 )

→ 10 = 5 a

→ a = 10 / 5

→ a = 2 m/s²

Therefore,

• Acceleration of Scooter is 2 m/s².

Answer 2

Answer:

✡ Question ✡

⬛ A scooter acquires a velocity of 36 km/hr in 5s just after the start. Calculate the acceleration.

✡ Given ✡

⬛ A scooter acquires a velocity of 36 km/hr in 5s just after the start.

✡ To Find ✡

⬛ Acceleration of scooter = ?

✡ 1st equation of motion:-

⭐ $\dfrac{(v-u)}{t}$ ⭐

✴ v = final velocity

✴ u = initial velocity

✴ t = time

✡ Solution ✡

✏ The scooter acquires a speed of 36km/hr in 5sec

✏ So the initial velocity is 0

✏ Final velocity is 36km/hr = $\dfrac{36×5}{18}$ = 10m/sec

✏ Time taken is 5sec

➡ Acceleration = $\dfrac{(v-u)}{t}$

=> $\dfrac{(10-0)}{5}$

=> $\dfrac{10}{5}$

=> 2m/sec²

∴ Acceleration of scooter is 2m/sec²

Explanation:

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