Question

a scooter acquires a velocity of 36 km per hour in 10 seconds just after the start calculate the acceleration of the scooter

Answer 1

u = 0 mps
v = 36 kmph = $(36*1000)/3600$ = 10 mps
t = 10s

since, $a = (v-u)/t$

a = 10/10 = 1mps^-2

hence accelaration = 1 metere per second^2