Question

a scooter acquires a velocity of 36 km per hour in 10 seconds just after the start calculate the acceleration of the scooter​

Answer 1

Solution :

First of all we've to convert the given velocity of 36 km/hr into metres per second because the time is given in seconds.

Now,

◆ 1 km = 1000 m

→ 36 km = 36 × 1000

= 36000 m

Also,

◆ 1 hour= 60 minutes

→ 60 × 60 seconds

→ 3600 seconds

So,

36 km/hr = 36000m/3600s

= 10 m/s

[You may convert the km/hr into m/second by multiplying it from 5/18]

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Thus,the given velocity of 36 km/hr is equal to 10 metres per second.

Now,

Initial velocity(u) = 0(Scooter starts from rest)

Final velocity(v) = 10 m/s

Time(t) = 10 seconds

◆ Acceleration = Final Velocity - Initial Velocity/time

→ a = (10 - 0)/10

→ a = 10/10

→ a = 1 m/s^2

Thus,the acceleration of the scooter is 1 m/s^2

Answer 2

Answer:

• The acceleration (a) of the scooter is 1 m/s²

Given:

1. Initial velocity (u) = 0 Km/s = 0 m/s
2. Final velocity (v) = 36 Km/h
3. time taken (t) = 10 Sec.

Explanation:

$\rule{300}{1.5}$

As, the acceleration is given in Km/h we need to convert it into m/s ,

Therefore,

From converting factor we know,

⇒ 36 Km / h = 36 × ( 5 / 18) m/s

⇒ 36 Km / h = 180 / 18

⇒ 36 Km / h = 10 m/s

So, now Final velocity v = 10 m/s.

$\rule{300}{1.5}$

$\rule{300}{1.5}$

From the formula we know,

⇒ a = ( v - u ) / t

Where,

• a Denotes Acceleration.
• v Denotes Final velocity.
• u Denotes Initial velocity.
• t Denotes Time period.

Now,

⇒ a = ( v - u ) / t

Substituting the values,

⇒ a = ( 10 - 0 ) / 10

⇒ a = 10 / 10

⇒ a = 1

⇒ a = 1 m/s²

∴ The acceleration (a) of the scooter is 1 m/s².

$\rule{300}{1.5}$