A scooter acquires a velocity of 36km/h in 10 sec Just after the start. It takes 20 sec to stop. Calculate the acceleration in two cases
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Answer:
0 m/s² and 0.5 m/s²
Explanation:
CASE 1
v = 36 km/ h = 10 m/s
t = 10 s
u = 0 [ as it starts from rest ]
a = v- u/t
a = 10 - 0 / 10
a = 0 [ the object is moving in uniform motion]
CASE 2
u = 10 m/s
v = 0 [ as it comes to rest ]
t = 20 s
a = v-u /t
a = 0 - 10/20
a = -1/2
r = 1/2 = 0.5 m/s²
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