Question

A scooter acquires a velocity of 36km/h in 10 sec just after the start it takes 20 sec to stop. Calculate its acceleration in 2 cases.... ​

Answer 1

Explanation:

u = 0m/s

v = 36km/hr = 10m/s

t = 10sec

v-u = at

a = (v-u)/t

(10-0)/10 = 1m/s²

u = 36km/hr = 10m/s

v = 0m/s

t = 20sec

a = (v-u)/t

(0-10)/20 = -0.5m/s²

Answer 2

Answer:

0.5m/s square

Explanation:

u= 0m/s

v=36 km/h

=10m/sec

a= 10 sec

a=(v-u)/t

(10-0)/10=1m/s square

u=36km/h

=10m/s

v= 0m/s

t= 20 sec

a= (v-2/t)

0-10/20=-0.5 m/s square

HOPE THIS HELPS YOU