A scooter acquires a velocity of 36km /hr in 10 sec just after the start . It takes 20 second to stop . Calculate the acceleration in two cases
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first case 1 m/s square in second case minus
o.5 m/second square
o.5 m/second square
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v= u + at
36km/h = 36*5/18 = 10m/s
10 = 0 + a1*10
a1 = 1m/s ^2
second equation,
0 = 10 - a2 * 20
10 = a2*20
a2 = -1/2
36km/h = 36*5/18 = 10m/s
10 = 0 + a1*10
a1 = 1m/s ^2
second equation,
0 = 10 - a2 * 20
10 = a2*20
a2 = -1/2
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