A scooter acqurires a volocity of 36km per hour in 10 second just after the start calculate the acceberation of the scooter
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dear Friend,
velocity after 10sec=36kmph=10mps=v
u=0mps
t=10sec
acceleration=(v-u)/t
=(10-0)/10
=10/10
=1 ms^2
hope it benefits u.
velocity after 10sec=36kmph=10mps=v
u=0mps
t=10sec
acceleration=(v-u)/t
=(10-0)/10
=10/10
=1 ms^2
hope it benefits u.
Answered by
0
Velocity (v) = 36 km/h = 10 m/s
Initial Velocity (u) = 0 m/s
Time (s) = 10 second
Acceleration = ?
Acceleration = (v-u)/t
Putting values:
Acceleration = (10-0)/10
= 10/10
= 1 m/s²
Initial Velocity (u) = 0 m/s
Time (s) = 10 second
Acceleration = ?
Acceleration = (v-u)/t
Putting values:
Acceleration = (10-0)/10
= 10/10
= 1 m/s²
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