Question

A scooter aquires a velocity of 36km/h in 10 sec just after start calculate the acceleration of the scooter

Answer 1

acceleration=velocity/time=36×5/18/10=10/10=1msec^-2

Answer 2

Solution :

Given :  

u (initial velocity) = 0 (rest) , v (final velocity) = 36 km/ hr = 36 × (1000/3600)

v = 36× 5/18 = 10 m/s. , t = 10s

From first equation of motion , v = u + at

10 = 0 + a ×10

10 = 10a

a = 10/10

a = 1 m/s²

acceleration of the scooter = 1 m/s²

Hence, the acceleration of the scooter is 1 m/s².

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