Question

A scooter from rest, moves in a straight line with a constant acceleration and covers a distance of 64 m in 4 sec. Calculate its acceleration and its final velocity?

Answer 1

easy
final velocity is given that is 64m/s
A=v-u/t=64-0/4=16m/s(u = 0)

Answer 2

U=0

D=64m

T=4sec

A=?

V=?

Apply second equation

S=ut+1/2at^

64=0*4+1/2*a*4^

64=0+1/2*a*16

64=1/2a*16

64=8a

A=64/8

A=8m/s^

Apply first equation

V=u+at

V=0+8*4

V=0+32

V=32m/s

Hope it will help u

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