A scooter going due east at 10msec-1 turns right through an angle of 90 degrees. If the speed of the scooter remains unchanged in talking this turn, I the change in the velocity of the scooter is ? ("Answer is 14.14msec-1 in the south west direction") say me the method plz.
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Expression for change in velocity:△v=√(v1^2+v1^2−2v1×v2cosθ)
whereθ=Angle between the velocities
Hence,△v=√{(10^2)+(10^2)-2×(10)(10)cos90
∆v= 10√2
∆v= 10 × 1.414
=14.14 m/s
whereθ=Angle between the velocities
Hence,△v=√{(10^2)+(10^2)-2×(10)(10)cos90
∆v= 10√2
∆v= 10 × 1.414
=14.14 m/s
ASiri08:
Say still more clearly plz
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