Question

a scooter is moving at a speed of 36 km is brought to rest in 10 sec. calculate retardation​

Answer 1

Answer:

$\huge \underline \mathbb {SOLUTION:-}$

 v=36 km/hr

 v=36×185=10 m/s

     u=0

    t=10 sec

     v=u+at

    10=0+a(10)

    10=10a

    a=1 m/s2

Answer 2

Given :

• A scooter is moving at a speed of 36 km is brought to rest in 10 seconds.

To Find :

• Retardation of the scooter = ?

Solution :

• Initial Velocity = 36 km/hr
• Final Velocity = 0 m/s
• Time period = 10 seconds

First of all convert the Initial Velocity from km/hr to m/s :

→ Final Velocity = 36 km/hr

→ Final Velocity = 36 × 5/18

→ Final Velocity = 18 × 5/9

→ Final Velocity = 2 × 5

→ Final Velocity = 10 m/s

Now, let's find the retardation by the scooter by using first equation of motion :

• v = u + at

Where,

• v = Final Velocity
• u = Initial Velocity
• a = acceleration
• t = time

Now, plug in the given values in above equation of motion :

➻ 0 = 10 + a(10)

➻ -10 = 10a

➻ a = -10 ÷ 10

➻ a = -1 m/s²

• Hence,the acceleration of the scooter is -1 m/s².
• Hence,the retardation of the scooter is 1 m/s².