Physics, asked by BrainyWarrior, 1 year ago

A scooter is moving with a velocity of 20 m/s .The mass of the scooter and the rider is 180 kg the constant force applied is 500 N a)how long should the brakes be applied to make the scooter come to a halt b) how far does it travel before coming to rest

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Answered by Anonymous
99
first we will have to find the time.

a) u (initial velocity) = 20 m/s

v (final velocity) = 0 m/s (as the vehical comes to rest)

m (mass) = 180 kg

force = -500 N ( as it comes to rest)

f = m(v-u)/t

so,

-500=180(0-20)/t

-500t=-360

t=360/500

t=0.72 s

b)s = ?

2as = v2-u2 (3rd equation of motion)

2x (v-u)/t x s= 0- 20x 20

2 x -27.7 x s = -400

s=400/55.4

s=7.22 m


BrainyWarrior: I didn’t understand y the force should be taken as negative
BrainyWarrior: Can u pls tell
Answered by sahooabhi135
28

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A scooter is moving with a velocity of 20 m/s .The mass of the scooter and the rider is 180 kg the constant force applied is 500 N a)how long should the brakes be applied to make the scooter come to a halt b) how far does it travel before coming to rest

Report by BrainyWarrior 28.07.2018

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NikiSwar06

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first we will have to find the time.


a) u (initial velocity) = 20 m/s


v (final velocity) = 0 m/s (as the vehical comes to rest)


m (mass) = 180 kg


force = -500 N ( as it comes to rest)


f = m(v-u)/t


so,


-500=180(0-20)/t


-500t=-360


t=360/500


t=0.72 s


b)s = ?


2as = v2-u2 (3rd equation of motion)


2x (v-u)/t x s= 0- 20x 20


2 x -27.7 x s = -400


s=400/55.4


s=7.22 m


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