Question

A scooter moving at 10ms-1 is stopped by applying brakes that produce a uniform retardation of 0.5ms-2. How much distance will it cover before stopping​

Answer 1

Answer:

A→B

U=10m/s,V=0,A=−0.5m/s

2

d=?

V

2

=U

2

+2ad

0=100−2(0.5)d

d=100m

Answer 2

Answer:

d=200 m

Explanation:

u=10 m/s

a=-0.5 m/s²

d=?

v=0 m/s (scooter comes at rest)

a=v-u/t

-0.5=0-10/t

t=10/0.5

t=20 sec

now

d=v*t

d=10*20

d=200 m