Question

A scooter moving at a speed of 10m/s² is stopped by applying brakes which produce acceleration of -0.5m/s². How much distance will be covered by the scooter?​ ​

Answer 1

Given :-

• A scooter moving at a speed of 10m/s is stopped by applying brakes which produce acceleration of -0.5m/s².

To find :-

• How much distance will be covered by the scooter?

Solution :-

• Initial velocity = 10 m/s

• Acceleration = - 0.5 m/s²

• Final velocity = 0

According to third equation of motion

→ v² = u² + 2as

Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " s " is distance.

→ (0)² = (10)² + 2 × (-0.5) × s

→ 0 = 100 - 1 × s

→ 0 = 100 - s

→ s = 100 m

Hence,

• Distance will be covered by the Scooter is 100m

More to know :-

• s = ut + ½ at² (second equation of motion)
• v = u + at (first equation of motion)
• Acceleration is the rate of change in velocity.
• Acceleration in negative is known as retardation

Answer 2

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: QuEsTiOn :- \: \star}}}}}$

A scooter moving at a speed of 10m/s² is stopped by applying brakes which produce acceleration of -0.5m/s². How much distance will be covered by the scooter?

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

❥ Distance covered by the Scooter = 100m

$\Large{\underline{\underline{\bf{Given:-}}}}$

❥ Speed ↠ 10m/s

❥ Acceleration ↠ -0.5m/s².

$\Large{\underline{\underline{\bf{Find:-}}}}$

❥ Distance

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

❥ Initial velocity = 10 m/s

❥ Acceleration = - 0.5 m/s²

❥ Final velocity = 0

Applying Third law of motion

v² = u² + 2as

" v " = final velocity

" u " = initial velocity

" a " = acceleration

" s " = distance

Some points to remember :-

❥ If body starts from rest, its Initial velocity = u = 0.

❥ If we drop a body from some height, its Initial velocity = u = 0.

❥ If body stops, its Final velocity = v = 0.

❥ If body moves with uniform velocity, its Acceleration = a = 0.

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ v² = u² + 2as

↠ (0)² = (10)² + 2 × (-0.5) × s

↠ 0 = 100 - 1 × s

↠ 0 = 100 - s

↠ s = 100 m

${\boxed{\bold{Therefore, \ Distance \ covered \ by \ the \ scooter \ is \ 100m}}}}$