Question

A scooter moving at the speed of 10m/s is stopped by applying brakes which produce a uniform acceleration of -0.5m/s^2.How much distance will be covered by the scooter before it stops?

Answer 1

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Given,

u=10m/s

v=0

a= -0.5m/s²

we know that,

v²=u²+2as

0²=10²+2(-0.5)s

0=100-1.0s

s=100m

•°• Distance travelled before stopped is 100m

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Answer 2

Explanation:

Given,

Initial velocity = 10 m/s, Final velocity = 0 m/s, Acceleration = -0.5 m/s^2

Distance = ?

v^2 - u^2 = 2as (Third Equation Of Motion)

0^2 - 10^2 = 2(-0.5)(s)

0 - 100 = -1s

-100 = -1s

s = 100 m