Question

A scooter of mass 120 kg is moving with a uniform velocity of 108 km h -1 . Calculate the force required to stop the vehicle in 0.1 s.

Answer 1

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Answer 2

» Initial Velocity = u = 108 km/hr

» u = 108 × 1000/3600 m/s

» u = 30 m/s
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» Final Velocity will be = 0

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» Time = 0.1 s

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» We know that :-

=> V = u + at

=> 0 = 30 + a×0.1

=> a = -30/0.1

=> a = -300 m/s²

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» [Note :- Negative Sing states that applied force will be in opposite direction of motion of the scooter ]

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» Now

» Force = Mass × acceleration

=> F = ma

=> F = 120×(-300)

=> F = -36000 N
_____________[ANSWER]

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» Hence the required Force to stop the vehicle is "-36000 N"

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