Question

A scooter starts from rest and accelerates uniformly & covers 37.5 meters in 5 seconds. Calculate the acceleration produced in the scooter
​

Answer 1

Answer:

idki3j 33u33o2k3 u3j33

Explanation:

idk oen4hejne

Answer 2

Answer:

Initial velocity of the scooter (u)= 5 m/s

Final velocity of the scooter (v) = 10 m/s

Time taken for change in velocity (t)= 5 d

Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s²

Distance covered during these 5 seconds, is found using the relation

s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m

So scooter covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.