Question

A scooter weighing 150kg together with its rider moving at 36 km/hr is to take a turn of radius 30m. What force on the scooter towards the centre is needed to make the turn possible? who or what provides this?

Answer 1

Mass, m=150 kg , 
Speed, v=36
km/hr =36000 m/3600
s =10 m/s 
Radius, r = 30 m   
Force needed to make the turn possible = mv²/r     =150x10x10/30 = 500 N

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Im not sure about the other part

Answer 2

The force acting on the scooter towards the center is 500 N.

Explanation:

It is given that,

Mass of the scooter, m = 150 kg

Speed of the rider, v = 36 km/hr = 10 m/s

Radius of the path, r = 30 m

On a circular path, the force acting on an object is called centripetal force. Its formula is given by :

$F=\dfrac{mv^2}{r}$

$F=\dfrac{150\ kg\times (10\ m/s)^2}{30\ m}$

F = 500 N

So, the centripetal force acting on the scooter towards the center is 500 N. The frictional force is providing the centripetal force.

Learn more :

Centripetal force

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