A scored 15% more marks than b's what percent less marks did b score than that of a's?
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- Let b's score be x .
- a's score = 115 x/100 = 23 x / 20
B is less than a = 23x/20 - x = 3x /20
So less % = 3x / 20 × 20/23 x × 100 = 300 / 23 %
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answer is 23% .......
let b score =115 /100
23/20
23/20×20 =23%
let b score =115 /100
23/20
23/20×20 =23%
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