a scored 30% marks and failed by 15 marks.b scored 40% marks and obtained 35 marks more than pass mark.the pass percentage is
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Answered by
15
Heya friend,
Solution is as follows-:
Let the total marks be x
then ,
CASE A
pass percentage would be=30% of x +15[+15 cause a got failed by 15 marks]
CASE B
pass percentage would be=40% of x-35[-35 cause he got 35 more than pass percentage]
ON equating[since both are pass percentage]
=>3x/10 +15=4x/10-35
on solving we get
=> x/10=50
=> x=500;=TOTAL MARKS
SUBSTITUTING THE VALUE OF X=500 in case A [30% of x +15]
we get,
=3/10*500+15
=165[Passing marks]
Pass percentage
=165/500*100=33%
SO, the pass percentage will be 33%
hope this helps!!!!
Solution is as follows-:
Let the total marks be x
then ,
CASE A
pass percentage would be=30% of x +15[+15 cause a got failed by 15 marks]
CASE B
pass percentage would be=40% of x-35[-35 cause he got 35 more than pass percentage]
ON equating[since both are pass percentage]
=>3x/10 +15=4x/10-35
on solving we get
=> x/10=50
=> x=500;=TOTAL MARKS
SUBSTITUTING THE VALUE OF X=500 in case A [30% of x +15]
we get,
=3/10*500+15
=165[Passing marks]
Pass percentage
=165/500*100=33%
SO, the pass percentage will be 33%
hope this helps!!!!
Answered by
1
Answer:
Step-by-step explanation:
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