a screen is placed 50 cm from a single slit which is illuminated with light of wavelength lambda . if distance between the first and third minima in diffraction pattern is 3 mm and width of slit is 0.2 mm
Answers
The width of slit is 0.2 mm.
Explanation:
=> The distance between the first and third minima in diffraction pattern, x:
x = x₂ - x₁ = 3 mm
= 3 * 10⁻³ m
=> The distance of a screen from a single slit, D:
D = 50 cm = 0.5 m
Wavelength λ = 6000A° = 6000 * 10⁻¹⁰ m
=> Now, x = λD/d
x₂ - x₁ =(3λ - λ)D/d
x₂ - x₁ = 2λD/d
d = 2λD / x₂ - x₁
d = 2*6000*10⁻¹⁰*0.5/3*10⁻³
d = 2 * 10⁻⁴ m
d = 0.2 mm
Thus, the width of slit is 0.2 mm.
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