Question

A screen is placed 50 cm from a single slit which is illuminated with 6000 angstrom light distance between the first and third minimum in the diffraction pattern is 3 mm what is the width of the slit

Answer 1

Answer:

0.2mm

Explanation:

The position of nth minima in the diffraction pattern is 

      xn=dnDλ

∴x3−x1=(3−1)dDλ=d2Dλ

d=x3−x12Dλ=3×10−32×0.50×6000×10−10=2×10−4m