A screw gauge has 50 divisions on its circular scale. the pitch of the screw gauge is 0.5 mm. what is the least count?
Answers
Answered by
5
Answer:
least count= 0.5/50
therefore,
leat count = 0.01mm
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Answered by
4
Answer:
0.01 cm
Explanation:
Number of divisions on circular head =50
Distance moved in two revolution =1 mm
Pitch = distance moved in 1 revolution = 1/2 =0.5 mm=0.05 cm
The least count = 0.05/5 = 0.01cm
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