Question

A screw gauge has 50 divisions on its circular scale. the pitch of the screw gauge is 0.5 mm. what is the least count?
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Answer 1

Answer:

least count= 0.5/50

therefore,

leat count = 0.01mm

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Answer 2

Answer:

0.01 cm

Explanation:

Number of divisions on circular head =50

Distance moved in two revolution =1 mm

Pitch = distance moved in 1 revolution =   1/2  =0.5 mm=0.05 cm

The least count = 0.05/5 = 0.01cm