A screw gauge has least count of 10 micrometre and its circular scale is divided into 100 equal divisions. one main scale division is====??? Please plllleeeaaasse explain
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1 m.s. division=?
l.c.=10*10^-6=m.s div./total circ. div.
so m.s div. =100*10^-5=1mm
l.c.=10*10^-6=m.s div./total circ. div.
so m.s div. =100*10^-5=1mm
alplali48:
Thanks
But I did not understand can you explain in a better way
i have written down formulae of least count(l.c.). rest everything is just calculation.
Ok thanks very much frnd
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