Science, asked by minminanaturalist, 1 day ago

a Sday Bob BOP A township is to treat 845000 liter of sewage per day which has of mgle. An oxcidation pond is used for the purpose the effluen have a BOD of 30 ongle. The , ( 70 kg of sday BOD / hectare / day. The required area in ha) 190 effluent can of the pond is :-​

Answers

Answered by anshmeena36
0

Answer:

We know, ;

Therefore,

Also,

Also, , or,

Sludge Production

Volume of Oxidation Pond =

Assuming depth to be 0.3 m, Surface Area (A) =

Algae production =

Total algal production = (15).(7400) = 111 kg/d

Assuming 1.3 Kg oxygen production per Kg algal production,

Oxygen Production = (1.3).(111) = 144.3 Kg/d

Since oxygen available is more that oxygen requirement, the design is adequate.

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