Chemistry, asked by asthajaino2399, 1 year ago

A sealed cylinder of length l and cross sectional area a contains n molecules of an gas at kelvin temperature t. What is the force acting on the area of cylinder marked a due to gas?

Answers

Answered by amritaraj
1

Answer:

Explanation:

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Answered by ilanhalioua
18

Answer:

\frac{NKbT}{l}

Explanation:

Formulas I will use:

-P=F/A

-n=n/Na

-PV=nRT = NKT (R=KNa)

- Volum of cilinder: A* l

1. F=PA

2. P = NKbT/V

3. P = NKbT/ A* l

4. F = \frac{NKbT}{A*l} * A

5. Cross out A

6. Final Answer :

F = \frac{NKbT}{l}

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