A sealed tube can withstand a pressure of 3 atm is filled with air at 27°C and 760mm pressure. Find the temperature above which it will burst.
I will mark brainliest if l got a good answer.
Answers
Answered by
41
Explanation:
Applying pressure temperature relationship,
P1/T1 = P2/T2
Given data are
P1= 760 mm Hg
T1 = 273+37 = 310 K
P2 = 3 atm = 2280 mm Hg
T2 =?
Substituting in the above equation we get,
P1/T1 = P2/T2
760 mm Hg/310K = 2280 mm Hg/T2
T2 = 2280*310/760
T2 = 930 K
By converting kelvin to degree C, the value of T2 = 657 degree C
GokulGanesan:
But temperature is 27°C . You have taken 37°C
Answered by
17
Answer:
Hope it helps ☺️
Explanation:
Convert Kelvin temperature into Celsius also ..
Attachments:
Similar questions