Question

A second coil of 300 turns is wound closely on the above toroid. If the current in the primary coil is increased from 0 to 2 A in 0.05s, obtain the induced emf in the second coil.

Answer 1

We have,

• No. of turns in second coil = 300
• Initial current = 0 A
• Final current = 2 A
• Time taken = 0.05 s

We know that,

• e = -N ( ∆Φ/∆t )

Where, e = induced emf

⠀⠀⠀⠀⠀N = number of loops/turns

⠀⠀⠀⠀⠀∆Φ = Change in flux

⠀⠀⠀⠀⠀∆t = Change in time

Put all the values in formula,

• e = -N ( ∆Φ/∆t )
• e = -300 ( 2 - 0/0.05 )
• e = -300 × 200/5
• e = -300 × 40
• e = -1200

Therefore, the induced emf is -1200 volt.

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