Question

A seconds pendulum is taken to a height where the value of g is 4.36ms-2. What will be its new time period

Answer 1

New time period will be 1.33 sec

Explanation:

We have given second pendulum

Time period of second pendulum T = 2 sec

Value of $g=4.36m/sec^2$

Time period of pendulum is equal to $T=2\pi \sqrt{\frac{l}{g}}$

$2=2\times 3.14\times  \sqrt{\frac{l}{4.36}}$

$0.3183= \sqrt{\frac{l}{4.36}}$

Squaring both side

$0.1013={\frac{l}{4.36}}$

$l=0.441m$

Now acceleration due to gravity $g=9.8m/sec^2$

So time period will be $T=2\times 3.14\times \sqrt{\frac{0.441}{9.8}}=1.33sec$

New time period will be 1.33 sec

Learn more

A seconds pendulum is taken to a place where acceleration due to gravity falls to one fourth . How is the time period of the pendulum affected, if at all? Give reason. What will be its new time period

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