A seconds pendulum is taken to a place where acceleration due to gravity falls to one fourth . How is the time period of the pendulum affected, if at all? Give reason. What will be its new time period
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g = 1/4 (Time Period is inversely proportional to square root of g)
Therefore, T will be doubled.
Since T of second's pendulum is 2 seconds, the new time will be = (2 x 2) = 4s
Therefore, T will be doubled.
Since T of second's pendulum is 2 seconds, the new time will be = (2 x 2) = 4s
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see attachment............
so put T1 = 2sec...because it's second pendulum and find T2 = 2× 2 = 4 sec
so put T1 = 2sec...because it's second pendulum and find T2 = 2× 2 = 4 sec
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