A seconds pendulum is taken to a place where acceleration due to gravity falls to one fourth . How is the time periof of the pendulum affected , if it all ? Why? Wht will be its new time period ?
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TIME PERIOD IS INVERSELY PROPORTIONAL TO THE SQUARE ROOT OF THE ACCELERATION
THUS,THE TIME PERIOD WILL BECOME TWICE OF THE ORIGINAL TIME PERIOD .
EXPLANATION:
T×T= 1/g
T×T= 1/1/4g
T×T =4g
T =2g
TIME PERIOD IS INVERSELY PROPORTIONAL TO THE SQUARE ROOT OF THE ACCELERATION
THUS,THE TIME PERIOD WILL BECOME TWICE OF THE ORIGINAL TIME PERIOD .
EXPLANATION:
T×T= 1/g
T×T= 1/1/4g
T×T =4g
T =2g
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